Instructions for Students to Study and Do Homework (2 Minutes)

2. HS:

Review lesson 4,5 SH 9.

III- TTBH:

1. Test: (5 minutes)

a. Question:

Let brown beans cross with white beans to get F1 with all brown beans. Let F1 self-pollinate to get F2 with a ratio of 3 brown beans: 1 white beans. Discuss and write a cross diagram from P to F2.

b. Answers - score sheet:

F1 homozygous all brown seeds P is purebred and brown seeds are dominant over white seeds. F2 gives a ratio of 3:1 follow Mendel's law of segregation. (3 points)

Gene convention: A - brown seeds, a - white seeds. (1 point)

Cross diagram: P: AA x aa ( 1 point)

Gp: A a (1 point) F1: Aa (100% brown beans) x Aa (1 point) GF1: A, a A, a (1 point)

F2: 1AA: 2Aa: 1aa (1 point)

3 brown seeds: 1 white seed (1 point)

2. New lesson:

Teacher activities

Student activities

Content

A. STARTUP

* Target :

- Stimulate students' interest in finding out what they already know about

- Train students' critical thinking skills.

* Method: Presentation, analysis, commentary

* Competency orientation: problem solving, cognitive ability

The teacher lets students play the Guessing game.

Through the process of reproduction, offspring inherit many characteristics similar to their parents and ancestors, but there are also many characteristics that are different from them. Why does this happen?

SP to be achieved after completing the activity:

Students pay attention;

Think about the problem;

Participate in reading comprehension activities to find answers to the warm-up situations,

From the above question-posing method, the teacher leads students into new activities: Knowledge formation activities.

B: KNOWLEDGE FORMATION

* Target :

Describe Mendel's two-trait cross experiment.

- Explain why Mendel deduced the law of independent segregation of allele pairs during gamete formation.

- Present the content of the law of independent assortment.

* Method: Presentation, analysis, commentary

* Competency orientation: problem solving, cognitive ability

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Instructions for Students to Study and Do Homework (2 Minutes)

1. Ask students to read section I of the textbook to recreate Mendel's experiment and complete the following requirements within 10 minutes:

- How did Mendel conduct a two-trait cross-breeding experiment on peas?

- Based on what could Mendel conclude that the pairs of genetic factors in that experiment segregated independently from each other during the process of gamete formation?

- State the content of the law of independent assortment.


2. For each content, ask 1 student to present and then let the whole class discuss and supplement.

> Teacher corrects for students to take notes.

Activity 2 : Cytological basis of the law of independent assortment

1. Introduce the video about hybridization of two traits and the cytological basis of the law of independent assortment.

2. Ask students to read the textbook section II, combine and reproduce grade 9 knowledge to briefly present the cytological basis of the law of independent assortment.

Activity 3: The meaning of Mendel's laws of inheritance.

1. Ask students to read Textbook section III and complete the following requirements within 5 minutes:

- Perform command section III textbook


Students read textbooks to recreate Mendel's experiments.


- Summary of Mendel's experiment.


- Analysis of the segregation ratio of each individual trait is 3:1. The probability of each F2 phenotype is equal to the product of the ratios of the pairs of traits that make them up pairs of genetic factors that determine different traits segregate completely independently of each other during the process of gamete formation.


- Present prepared content, make additional comments, and take notes.


Students explain the cytological basis of the law of independent assortment.


- Follow the teacher's introduction


- Watch the video, read the textbook and present the basics of cytology.


Students carry out the commands of part III of the textbook and state the meaning of Mendel's laws of inheritance.


- Read textbook

I/ Experiment of crossbreeding two traits. (15')

Pt/c VT x XN F 1 : 100% VT F 1 x F 1

F 2 : 9VT:3VN:3XT:1XN

Analysis of experimental results: V: X = 3: 1

T : N = 3:1

=> each trait is inherited independently.

3. Content of the law of independent assortment: Pairs of genetic factors that determine different traits separate independently during the process of gamete formation.


II/ Cytological basis. (10')

Independent segregation and free combination of homologous chromosome pairs in gamete formation lead to independent segregation and free combination of allele pairs.


III/ The meaning of Mendel's laws. (10')

- When we know that a certain trait is inherited according to Mendel's law, we can predict the cross-breeding results.

- Explain the cause

Activity 1: Experiment of crossbreeding 2 traits:


2. For each given request, call on a few random students to answer, ask the whole class to follow and comment.

3. Comment, supplement and improve knowledge for students to take notes


- Perform command section III textbook

- practical significance: Predicting the results of separation in the next life

- Theoretical significance: Explains the diversity of living things (recombination variation appears descendants have differences from parents and ancestors).

- Answer each corresponding content and comment.

- Take notes

the cause of the recombination variation

C: PRACTICE

Objective: - Practice to help students consolidate what they already know.

- Train students' self-study skills, communication and cooperation skills, and problem-solving skills.

Teaching method: Assigning homework

Competency development direction: problem solving, communication skills, cognitive skills.

* How to proceed:

- The teacher gives us a situation with multiple choice questions.

- Students do exercises and multiple choice questions in groups (4 groups).

Question 1: In humans, phenylketonuria is caused by a recessive gene mutation located on an autosomal chromosome. A normal father and mother have their first daughter with phenylketonuria. The probability that they will have a son and not have the disease is

A. 1/2 B. 1/4

C. 3/4 D. 3/8

Show answer

Answer: D

Question 2: In sheep, the gene that determines coat color is located on the autosome. The allele A that determines white coat color is completely dominant over the allele a that determines black coat color. A male sheep is crossed with a female sheep, both of which are heterozygous. The lamb born is a white male sheep. If the lamb is crossed back to the mother, what is the probability of having a black-haired female sheep?

A. 1/4 B. 1/6

C. 1/8 D. 1/12

Show answer

Answer: D

3. The cytological basis of the law of independent division is

A. Independent segregation and free combination of homologous chromosome pairs in gamete formation lead to independent segregation and free combination of allele pairs.

- Present the practical and theoretical significance of Mendel's laws.

due to the inheritance of pairs of alleles on a chromosome together.

4. A plant species has gene A for tall plants, gene a for short plants; gene B for red fruit, gene b for white fruit. The genes are inherited independently. The hybrid has one phenotype of short plants and white fruit, accounting for 1/16. The genotypes of the parent plants are

AaBb x Aabb. B. AaBB x aaBb.

Aabb x AaBB. D. AaBb x AaBb. Answers 1A, 2D.

D: APPLICATION (8')

Objective: - Create opportunities for students to apply acquired knowledge and skills to new situations and contexts, especially in real life.

-Training thinking and analytical skills.

Teaching methods: Group teaching; problem-solving teaching; presentation method; use of visual aids

Capacity development orientation: Experimental capacity, observation capacity, creative capacity, communication capacity. Self-confidence, independence, communication.

Explain why it is impossible to find two people with identical genotypes on Earth, except in the case of identical twins.

Solution:

In reality, it is impossible to find two people with identical genotypes (except in the case of identical twins) because the number of combinatorial variations that a pair of parents can produce is very large (2 23 × 2 23 = 2 46 different zygote types).

E: EXPAND (2')

Objective: To explore and expand knowledge, summarize all the knowledge learned

Teaching method: Assigning tasks

Capacity development orientation: autonomy-self-study, understanding nature and society, problem solving

Mind mapping

independent assortment, free combination of chromosomes. genes located on chromosomes.

4. Guide students to study and do homework (2 minutes)

1. Complete the command in part II

2. Study the lesson and answer the questions and exercises in the textbook on pages 66 and 67.


Lesson 10 - Lesson 10: GENE INTERACTION AND PLUS EFFECT OF GENE


I. OBJECTIVES

1. Knowledge:

After completing this lesson, students should be able to

- Identify gene interactions through Mendel's phenotypic segregation ratio changes in two-trait crosses.

- Explain what additive interaction is and state the role of additive genes in determining quantitative traits.

- Explain that a gene can determine many different traits, through a specific example of the gene that determines sickle cell anemia in humans.

-Give examples of traits controlled by multiple genes (cumulative effects) and examples of pleiotropic effects of genes.

2. Skills:

- Develop observation skills.

- Develop skills in analyzing experimental results.

3. Attitude : love nature and creatures

4. Capacity development

a/ Knowledge capacity:

- Students can determine what the learning objectives of the topic are .

- Practice and develop analytical and generalizing thinking skills.

- Students can set up b/ Life skills:

many questions about the subject

episode

- Ability to demonstrate confidence when presenting ideas in front of groups, teams, and classes.

- Ability to present thoughts/ideas; collaborate; manage time and assume responsibility, in group activities.

- Ability to search and process information.

- Self -management : Be aware of the factors that affect you : impact on

learning process such as friends, learning tools, teachers...

- Correctly identify the rights and obligations of learning the subject...

- Team management : Listening and positive feedback , creating

II. TEACHING METHODS AND TECHNIQUES

1. Teaching methods

- Problem posing and solving methods…

open source

set ...

- Group teaching method, verification method

2. Teaching techniques

-Lightning technique, feedback technique in teaching, brainstorming technique.


II- preparation:

1. Teacher:

Figure 10.1, 10.2 Textbook.

2. HS:

III. Method:

- Presentation, visual.

IV Lesson progress:

1. Review: (5 minutes)

a. Question:

When crossing two purebred lines of beans with purple, smooth seeds and white, wrinkled seeds, the F1 line produces all beans with purple, smooth seeds. Allowing the F1 to self-pollinate will yield F2 with what ratio of genotype and phenotype? Knowing that the above cross follows Mendel's law of independent assortment.

b. Answers - score sheet:

- We see that F1 has all purple, smooth beans Purple>white, Smooth>wrinkled. To determine F2 we must write a cross diagram. (2 points)

Convention: A- purple seeds, a - white seeds. (1 point)

B – smooth seeds, b – wrinkled seeds.

Cross diagram: P t/c : AABB (purple, smooth) x aabb (white, wrinkled seeds) (3 points)

G p AB ab

F 1 : AaBb (all purple, smooth beans) x AaBb

GF1 AB, Ab, aB, ab AB, Ab, aB, ab

F2 ( 2 points)


AB

Ab

aB

ab

AB

AABB

AABb

AaBB

AaBb

Ab

AABb

AAbb

AaBb

Aabb

aB

AaBB

AaBb

aaBB

aaBb

ab

AaBb

Aabb

aaBb

aabb

F2 has the ratio of KG: 1 AABB KH: 9 A- B-: Purple, smooth beans. (3 points)

2 AABb 3 A- bb : Purple, wrinkled beans.

2 AaBB 3 aaB- : White, smooth beans.

4 AaBb 1 aabb : White, wrinkled beans. 2 Aabb

1 AAbb

2 aaBb

1 aaBB

1 aabb

2. New lesson:

Teacher activities

Student activities

Content

A. STARTUP

* Target :

- Stimulate students' interest in learning new lessons

- Train students' critical thinking skills.

* Method: Presentation, analysis, commentary

* Competency orientation: problem solving, cognitive ability

Question: (1') In Mendel's experiment, when crossing purebred parents differing by 2 contrasting traits, F1 heterozygous for 2 pairs of genes produced a hybrid generation consisting of 16 combinations. So is it possible to cross parents belonging to 2 purebred lines differing by only one trait, but the offspring

Does F2 also have 16 combinations? To answer this question, we study today's lesson .

B: KNOWLEDGE FORMATION

* Target :

- Identify gene interactions through Mendel's phenotypic segregation ratio changes in two-trait crosses.

- Explain what additive interaction is and state the role of additive genes in determining quantitative traits.

- Explain that a gene can determine many different traits, through a specific example of the gene that determines sickle cell anemia in humans.

* Method: Presentation, analysis, commentary

* Competency orientation: problem solving, cognitive ability

Activity 1: Guide students to learn the concept of relativity.


I/ Gene interaction.

Gene interaction is the influence

Require students to read textbook section I-1 and do the following:

- State the concept of gene interaction. Teacher explains what a non-allelic gene is.

Teachers provide students with some common ratios of complementary interaction styles.

The teacher gives the experiment and asks the students:

- Please state the similarities and differences between the cross experiment in complementary interactions compared to Mendel's two-trait cross experiment.

- From the phenotypic ratio in F 2, what can we conclude about the genotype of F 1 ?

- Summarize TN and write the theorem from P to F 2 .

3. For each given request, call on a few random students to answer, ask the whole class to follow and comment.

3. Comment, supplement and complete knowledge for students to take notes.


Activity 2: Guide students to learn the nature of additive interaction (10 minutes)

1. Ask students to read section I-2 and observe figure 10.1 in the textbook to complete the following content:

- What is cumulative interaction?

- Give an example of a trait that is caused by many factors.

Students learn about the concept of gene interaction and complementary interactions.

- Read section I-1. Textbook


- State the concept of gene interaction.


Students review Tno and compare to find the law of inheritance.

- Same: Pt/c; F 1 is homosexual; F 2 has 16 combinations.

- Different: P is the same; F 1 is different from P; F 2 phenotypic ratio

≠ 9:3:3:1.

- Because F 2 gives 16 combinations => F 1 is heterozygous for 2 gene pairs.


- Write the SDL like the textbook


- Present each of the above contents

- Comment


- Take notes


Students explore the nature of additive interaction.


- Read textbook section I-2

between genes in the process of trait formation (non-allelic genes)

1. Additional interactions:

- Ratio: 9:7; 9:6:1;

9 :4 :3 ;......

- TN: Crossbreeding in pumpkin Pt/c: Round x Round F 1 100% flat F 1 x F 1

F 2 9 flat: 6 round: 1 long.

- Explain:

F 2 has 16 gene combinations => each side of F 1 must give 4 types of gametes

=> F1 is heterozygous for 2 pairs of genes located on 2 different pairs of homologous chromosomes. However, the segregation ratio is not 9:3:3:1 as Mendel's law but there are only 3 types of phenotypes of the same fruit shape trait. So we can conclude that the squash shape trait is determined by 2 pairs of genes located on 2 different pairs of chromosomes and interact with each other in a complementary interaction style.

Suppose when two dominant alleles A and B appear at the same time, the result is flat fruit.

When there is only 1 of 2 dominant alleles A or B, the fruit will be round.

When there is no dominant allele, the fruit is long.

Textbook

- KN: Complementary interaction is the interaction of 2 or more non-allelic genes that gives rise to new phenotypes.

2. Cumulative interaction:

- Ratio: 15:1; 1:4:6:4:1;

........

- Concept: It is a type of interaction in which each gene of the same type

contribute equally to the

Gene expression and complementary interaction (17')

- What types of traits are governed by this type of interaction?

- In the cross of 2 traits, the conclusion that there is definitely gene interaction is based on the phenotype of which hybrid generation?

2. For each given request, call on a few random students to answer, ask the whole class to follow and comment.

3. Comment, supplement and complete knowledge for students to take notes.

Activity 3: Guide students to learn about the pleiotropic effects of genes (7')

1. Ask students to read section II and observe figure 10.2 in the textbook and answer the following questions:

- Describe the concept of pleiotropic genes?

- What are the manifestations that show whether the HbS mutant gene is a pleiotropic gene?

- What are the consequences when a pleiotropic gene mutates?

2. For each given request, call on any number of students to answer, ask the whole class to follow and comment.

3. Comment, supplement and complete knowledge for students to take notes.

4. Depending on the students, teachers can introduce some other forms of interaction (overwhelming).

Activity 4: Consolidation : (4 minutes) Teacher guides students to answer some multiple choice questions:

1 In case each gene is of the same type (dominant or recessive of genes)

and observe the picture

10.1 Solve the requirements set by the teacher

- Each gene of the same type contributes equally to the formation of traits.


- Quantitative traits.


- Phenotypic ratio in F2 generation .

- Present each of the above contents

- Comment

- Take notes


Students learn about the pleiotropic effects of genes.

- The effect of a gene on the expression of many traits

- The appearance of a series of pathological disorders in the body

- Mass change of traits controlled by genes.

- A few students answer, the whole class watches and comments.

- Students study more of Mendel's examples.

- Take notes

trait formation

- Traits that are determined by many genes in an additive interaction are often quantitative traits.

- Me:

Pt/c: red flower x white flower F 1 100% rose flower F 1 x F 1

F 2 : 1 red: 4 light red: 6 pink: 4 light pink: 1 white.

- Explanation is similar to above but based on different ratios.


II/ Pleiotropic effects of genes.

Pleiotropic genes are genes that can affect the expression of multiple traits.

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