Overview of Transformer Station Selection, Voltage Level Selection, Power Supply Diagram.


- Required illuminance: E= 50 lux

- Calculated height h tt = 4.7m

- Lighting with high pressure sodium lamp, 1 bulb/lamp set. After running Luxicon software, we get the following results:

- Average illuminance: E tb = 55 (lux)

- Number of light sets used N = 4 sets (4 bulbs)

- Power of each bulb (including Ballast): 175 W

- Cos coefficient = 0.6 From that we can calculate:

P cs4 ​​= 4*175 = 700W = 0.7kW

Q cs5 ​​= P cs5 * tg = 0.7* 1.33 =0.93 kVAr.

In addition, we also provide local lighting in special locations that require increased illuminance with P cscb = 0.5 kW; Q cscb = 0.67 kVAr

From there we determine the lighting load for the entire workshop A (including offices and warehouses):

P csxA = P cs1 + P cs2 + P cs3 +P cs4 ​​+P cs5 + P cscb

= 5.85 +1.03+0.34+0.34+0.7+P cscb 0.5= 8.77 kW

Q csxA = 7.8+1.37+0.46+0.46+0.93+0.67 = 11.7 kVAr.

Thus, we have determined the lighting load of workshop A, the remaining workshops are also determined similarly, the results are given in table 2.5ï

Determine office dynamic load:

In addition to the amount of electricity used for lighting, in offices and administrative buildings there are also dynamic loads (computers, fans, air conditioners, etc.), so we also need to determine the dynamic load for office areas. However, due to the lack of complete data on the capacity of the equipment, here we determine the power consumption according to the rated current and coefficient K nc.

Determine the dynamic load of the office:

P tt = P dm * K nc = I dm *U dm *cosφ*K nc (2.22) Q tt = P tt * tgφ

K nc : Demand coefficient, choose based on experience or look up in books

technical hand


For 25 m² office:

We choose Iđm = 10A, Uđm = 220V, cosφ=0.8.

Choose K nc =0.7 P dm =10*10 -3 *220*0.8 =1.76 kW

P ttvp =P dm *K nc = 1.76*0.7 =1.23 kWr.

Q ttvp = P ttvp * tg = 1.23*0.75 = 0.92 kVAr.


With office S= 100 m²:

We choose I dm = 30 A, U dm = 220V, cosφ = 0.8. Choose K nc = 0.7

P dm =30*10 -3 *220*0.8 =5.28 kW

P ttvp =P dm *K nc = 5.28*0.7 =3.7 kWr.

Q ttvp = P ttvp * tg = 3.7*0.75 = 2.77 kVAr.

The calculation results are given in table 2.5 page 28.

Chapter 2 Determining the calculated load Instructor: Ms. Nguyen Thi Quang

Table 2.5 Lighting load table and office power load table

Factory name - load

Lighting load

Office dynamic load

Area S(m²)

Illuminance requirement E (lux)

Type

lamp

Number of lights/set

CS

P lamp (W)

Number of light sets

N

E tb

(lux)

Q

information

)

HS

LLF decline

P cs (kW)

cos

Q cs (k

VAr)

I dm (A)

P dm (A)

cos

K nc

P dlvp

(kW)

Q dlvp (k VAr)

Factory A:

Factory A

1075

200

HQ

2

43

68

198.8

3200

0.75

5.85

0.6

7.80







Local CS



HQ


43




0.50

0.6

0.67







KT Office

25

300

HQ

2

43

4

282.2

3200

0.75

0.34

0.6

0.46

10

1.76

0.8

0.7

1.23

0.92

Factory

25

300

HQ

2

43

4

282.2

3200

0.75

0.34

0.6

0.46

10

1.76

0.8

0.7

1.23

0.92

Company office

100

300

HQ

2

43

12

300.8

3200

0.75

1.03

0.6

1.37

30

5.28

0.8

0.7

3.70

2.77

Warehouse A

650

50

NTCA

1

175

4

55

16000

0.79

0.7

0.6

0.93







Total (CSA).










8.77


11.69





6.16

4.62

B & C Workshop

Factory B

1325

200

HQ

2

43

86

206.4

3200

0.75

7.40

0.6

9.87







Factory C1

150

200

HQ

2

43

15

220.1

3200

0.75

1.29

0.6

1.72







Factory CS C2

120

200

HQ

2

43

12

209.8

3200

0.75

1.03

0.6

1.37







Local CS



HQ


43





0.50

0.6

0.67







KT Office

25

300

HQ

2

43

4

282.2

3200

0.75

0.34

0.6

0.46

10

1.76

0.8

0.7

1.23

0.92

KT Office

25

300

HQ

2

43

4

282.2

3200

0.75

0.34

0.6

0.46

10

1.76

0.8

0.7

1.23

0.92

Factory

25

300

HQ

2

43

4

282.2

3200

0.75

0.34

0.6

0.46

10

1.76

0.8

0.7

1.23

0.92

Workshop

25

300

HQ

2

43

4

282.2

3200

0.75

0.34

0.6

0.46

10

1.76

0.8

0.7

1.23

0.92

Warehouse C

120

50

NTCA

1

175

1

65.4

16000

0.79

0.30

0.6

0.40







Lobby

60

50

HQ

1

43

4

50

3150

75

0.17

0.6

0.23







Total (CSB).










12.07


16.09





4.93

3.70

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Overview of Transformer Station Selection, Voltage Level Selection, Power Supply Diagram.


Graduation thesis Page 27 Student: Ta Minh Hien

Chapter 2 Determining the calculated load Instructor: Ms. Nguyen Thi Quang


2.6.4 Determine the calculated load for the factory.

Determine the calculated load of the entire workshop A (PP1):

With the number of circuits entering the PP1 cabinet being 5, we choose K dt = 0.85 (TL[4], tr13;TL[1], tr595) P ttpp1 = K dt * P ttđl1

= 0.85(76.95+86.62+90.4+85.08+14.53) = 302.24 kW.

Q ttpp1 = K dt * Q ttdli

= 0.85(65.97+48.07+43.02+45.9+15.78) = 185.93 kVAr.

S ttpp1 = I ttpp1 =


354.85

=354.85 kVA

302.24 2 185.93 2

3 * 0.38

= 539.14 A


Determine the calculated load for workshops B and C: Choose K dt = 0.85

P ttpp2 = K dt * P ttđl

=0.85(79.19+78.16+84.25+89.35+89.35+17+27.8+36.3)=426.19kW

Q ttpp2 = K dt * Q ttdli

=0.85(60.02+59.3+48.9+49.51+49.51+19.79+16.69+23.51)

=279.87kVAr


S ttpp1 = I ttpp1 =


509.87

=509.87 kVA

426.19 2 279.87 2

3 * 0.38

= 774.66 A

Calculated load of factory: Choose K dt = 0.95

P tt NM = K dt * P ttpp =0.95*(306.2+426.19) = 692.01 kW Q tt NM = K dt * Q ttpp = 0.95*(185.93+279.87) = 442.51 kVAr

692.01 2 442.51 2

S ttNM I ttNM =


821.4

= 821.4 kVA

3 * 0.38

= 1248 A

The results of the calculated load of the factory are given in Table 2.6.

Determining the PTTT is a very important and necessary step in the process of designing a power supply system. The results obtained will be the basis for selecting transformers, conductors, etc. in the following chapters.


Graduation thesis Page 28 Student: Ta Minh Hien

Chapter 2 Determining the calculated load Instructor: Ms. Nguyen Thi Quang



Table 2.6 Load table for calculating factory inventory

STT

Device group name

Total P dm

Power (kW )

Q ttđl (kVAr)

Power (kW )

Q ttcs (kVAr)

Power (kW )

Q tt (kVAr)

K coefficient

Power (kVA )

I tt (A)

(1)

(2)

(3)

(4)

(5)

(6)

(7)

(8)

(10)

(9)

(10)

(11)

Factory A (PP1).











1

Group 1 (DL1A)

106.00

76.95

65.97



76.95

65.97


101.36

154.00

2

Group 2 (DL2A)

102.50

88.62

48.07



88.62

48.07


100.82

153.18

3

Group 3 (DL3A)

103.00

90.40

43.02



90.40

43.02


100.11

152.11

4

Group 4 (DL4A)

103.50

85.08

45.90



85.08

45.90


96.67

146.88

5

Group 5 (CSA)


6.16

4.62

8.77

11.69

14.95

16.31


21.45

32.59

Total workshop load A (cabinet PP1):





302.24

185.93

0.85

354.85

539.14

Workshop B and C (PP2)


1

Group 1 (DL1B)

104.50

79.19

60.02



79.19

60.02


99.37

150.97

2

Group 2 (DL2B)

104.50

78.16

59.30



78.16

59.30


98.11

149.06

3

Group 3 (DL3B)

103.00

84.25

48.90



84.25

48.90


97.41

148.00

4

Group 4 (DL4B)

102

89.35

49.51



89.35

49.51


102.15

155.20

5

Group 5 (DL5B)

102

89.35

49.51



89.35

49.51


102.15

155.20

6

Group 6 (CSB)


4.93

3.70

12.07

16.09

17.00

19.79


26.09

39.64

7

Group 6 (DL1C)

84.85

27.80

18.69



27.80

18.69


33.50

50.90

8

Group 7 (DL2C)

71.50

36.30

23.54



36.30

23.54


43.26

65.73

Total load of workshop B&C (PP2)





426.19

279.87

0.85

509.87

774.66

Total plant load balance (PPC)





692.01

442.51

0.95

821.40

1247.99



Graduation thesis Page 29 Student: Ta Minh Hien


Chapter 3

SELECTING TRANSFORMERS AND BACKUP GENERATORS


3.1 Select transformer:

3.1.1 Overview of transformer station selection, voltage level selection, power supply diagram.

Transformer station:

Transformer station is used to convert voltage from one voltage level to another.

It plays a very important role in the power supply system.

- According to the task, people divide transformer stations into two types:

+ Intermediate transformer station or also known as main transformer station: This station receives electricity from the 35  220kV system , converts it to 15kV, 10kV, or 6kV voltage levels, sometimes down to 0.4 kV.

+ Workshop transformer station: This station receives electricity from the intermediate transformer station and converts it into appropriate voltage levels to serve the loads of factories, workshops, or consumers. The primary side usually has voltage levels: 6kV, 10kV, 15kV, .... The secondary side usually has voltage levels: 380/220V, 220/127V., or 660V.

-In terms of structure, people divide it into indoor stations and outdoor stations.

+ Outdoor BA substation: In this substation, the high voltage equipment is placed outdoors, while the low voltage distribution part is placed indoors or in prefabricated iron cabinets specifically used for distribution to the low voltage side. Small capacity transformer stations ( 300 kVA) are placed on pillars, while large capacity stations are placed on concrete or wooden foundations. Building an outdoor substation will save costs compared to an indoor substation.

+ Indoor BA station: At this station, all electrical equipment is placed.

in the house

- Select location, quantity and capacity of transformer stations:

In general, the location of the transformer station needs to meet the following requirements:

- Near load center, convenient for power supply.

- Convenient for operation and management.

- Save investment costs and operating costs, etc.

However, the final location chosen also depends on other conditions such as: Ensuring the space does not obstruct other activities, aesthetics, etc.

Select voltage level: Because the factory is supplied with electricity from a 15kV line, and the factory's load only uses 220V and 380V voltage. Therefore, we will install a 15/0.4kV step-down transformer station to supply electricity to the factory's load.

Power supply diagram:


With low voltage power grids supplying factories and households, people usually follow two main wiring diagrams:

-Ray diagram:


M

MM


Figure 3.1 Circuit diagram and ray diagram

This diagram has the advantages of: high reliability, easy to implement protection and automation plans, easy to operate, etc. But the disadvantage is high investment capital.

-Branch diagram:



M

M

M

Figure 3.2 Branch circuit diagram

For this scheme, the cost is lower, the flexibility is higher when it is necessary to change the technological process, rearrange the machines, but the disadvantage is that the reliability of the power supply is not high.

The ray diagram is used when there are concentrated consumers at the distribution point. The branch diagram is used in long rooms where consumers are spread out next to each other.

For the power supply network for Tien Tan plastic factory, we will use a combination of the two diagrams above. Large capacity devices will be wired separately (ray diagram), while medium and small capacity devices can be connected together (branch diagram).

3.1.2 Select quantity and capacity of MBA :

Regarding the number of MBAs, there are usually options: 1 MBA, 2 MBAs, 3MBAs.


- Option 1 MBA: For type 2 and type 3 consumers, we can choose the option of using only 1 MBA. This option has the advantage of low cost, simple operation, but the reliability of power supply is not high.

- Option 2 MBA: This option has the advantage of high reliability of power supply but the cost is quite high so it is often only used for households with large or important capacity (type 1 households).

- Option 3 MBA: Power supply reliability is very high but the cost is also very high so it is rarely used, usually only used for especially important consumers.

Therefore, depending on the importance of the consumer, as well as economic criteria, we choose the appropriate option.

3.1.2.1 Concept of MBA overload:

When calculating the selection of an MBA, often the simple selection method is based on the allowable overload conditions of the MBA.

Systemic overload or normal overload of the transformer

pressure:

This rule applies when in normal daily mode there are

when the transformer operates under load (K 1 < 1) and sometimes under overload (K 2 > 1).

The calculation sequence is as follows:

- Based on the load graph through the transformer, choose a transformer with a capacity less than S max and greater than S min (S max > S b > S min )

- The load graph through the transformer is converted into a load graph with only

two levels K 1 and K 2 with overload time T 2 .

- From the load capacity curve of the transformer (MBA) with corresponding capacity and ambient temperature, determine the allowable overload capacity K 2cp corresponding to K 1 , K 2 and T 2 .

- If K 2cp > K 2 means that the selected MBA is capable of operating with the diagram.

given load where the transformer's hottest point temperature ( cd ) is never

>140 0 C and the transformer life is still guaranteed.

-If K 2cp < K 2 , the selected transformer does not have protection capability.

To ensure the above two conditions, a transformer with a larger capacity must be selected.

When choosing an MBA with a capacity greater than S max, there is no need to re-check this capability.

Multi-step load curve isometric approach to two-step load curve:

- Based on the selected S dmB, calculate the load factor Ki of the load graph levels.

Ki =

S i S dmB

K i > 1: overload (3.1)

Ki < 1: under load

- Determine K 2 , T 2 by isotropy of the region with K i > 1 according to the formula:

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