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Car body electrical practice - 8 zt2i3t4l5ee zt2a3gs zt2a3ge zc2o3n4t5e6n7ts If the voltage is out of specification, replace the wire or connector. If the voltage is within specification, install the front fog light relay and follow step 5. Step 5 Check the front fog light switch - Remove the D4 connector of the fog light switch - Use a multimeter to measure the resistance of the front fog light switch. Measurement location Condition Standard D4-3 (BFG) -D4-4 (LFG) Light switchFront Fog OFF >10kΩ D4-3 (BFG) -D4-4 (LFG) Front fog light switchON <1 Ω - Standard resistor D4 connector is located on the combination switch assembly. If the resistance is out of specification, replace the combination switch (the fog light switch is located in the combination switch). If the resistance is within specification, follow step 6. Step 6 Check wiring and connectors (front fog light relay-light selector switch) - Disconnect connector D4 of the combination switch assembly - Use a voltmeter to measure the voltage value of jack D4 on the wire side. Measurement location Control modecontrol Standard D4-3 (BFG) - (-) AQ TAIL 11 to 14 V D4 connector for the wiring of the combination switch assembly If the voltage does not meet the standard, replace the wire or connector. If the voltage is within standard, there may have been an error in the previous measurements. Step 7 Check the front fog lights - Remove the front fog light electrical connector. - Supply battery voltage to the fog lamp terminals Jack 8, B9 of front fog lamp on the electrical side blind first. Power supply location Terms and Conditions Battery positive terminal - Terminal 2Battery negative terminal - Terminal 1 Fog lightsbefore morning - If the light does not come on, replace the bulb. If the light is on, re-plug the jack and continue to step 8. Step 8 Check wiring and connectors (relay and front fog lights) - Disconnect the B8 and B9 connectors of the front fog lights. - Use a voltmeter to measure voltage at the following locations: Measurement location Switch location Terms and Conditions B8-2 - (-) AQ Electric lock ON TAIL size switchFog switch ON 11 to 14 V B9-2 - (-) AQ Electric lock ONTAIL size switch Fog switch ON 11 to 14 V B8 and B9 connectors on the front fog lamp wiring side Voltage is not up to standard, repair or replace the jack. If up to standard, there may have been an error in the measurement process. 2.2.4. Procedure for removing, installing and adjusting fog lights 1. Procedure for removing - Remove the front inner ear pads Use a screwdriver to remove the 3 screws and remove the front part of the front inner ear liner -Remove the fog light assembly + Disconnect the connector. + Use a screwdriver to remove 3 screws to remove the fog light cover 2. Installation sequence -Rotate the fog lamp bulb in the direction indicated by the arrow as shown in the figure and remove the fog lamp from the fog lamp assembly. -Rotate the fog light bulb in the direction indicated by the arrow as shown in the figure and install the light into the fog light assembly. - Use a screwdriver to install the fog light cover -Install the electrical connector Attention: Be careful not to damage the plastic thread on the lamp assembly. - Install the front inner ear pads Use a screwdriver to install the front inner bumper with 3 screws. 3. Prepare the vehicle to adjust the fog light convergence. Prepare the vehicle: - Make sure there is no damage or deformation to the vehicle body around the fog lights. - Add fuel to the fuel tank - Add oil to standard level. - Add engine coolant to standard level. - Inflate the tire to standard pressure. - Place spare tire, tools and jack in original design position - Do not leave any load in the luggage compartment. - Let a person weighing about 75 kg sit in the driver's seat. 4. Prepare to check the fog light convergence a/ Prepare the vehicle status as follows: - Place the car in a dark enough place to see the lines. The lines are the dividing line, below which the light from the fog lights can be seen but above which it cannot. - Place the car perpendicular to the wall. - Keep a distance of 7.62 m between the center of the fog lamp and the wall. - Park the car on level ground. - Press the car down a few times to stabilize the suspension. Note: A distance of approximately 7.62 m is required between the vehicle (fog lamp center) and the wall to adjust the convergence correctly. If the distance of 7.62 m cannot be achieved, set the correct distance of 3 m to check and adjust the fog lamp convergence. (Since the target area varies with the distance, please follow the instructions as shown in the figure.) b/ Prepare a piece of thick white paper about 2 m high and 4 m wide to use as a screen. c/ Draw a vertical line through the center of the screen (line V). d/ Set the screen as shown in the picture. Note: - Keep the screen perpendicular to the ground. - Align the V line on the screen with the center of the vehicle. e/Draw the reference lines (H, V LH and V RH lines) on the screen as shown in the figure.HINT: Mark the center of the fog lamp on the screen. If the center mark cannot be seen on the fog lamp, use the center of the fog lamp or the manufacturer's name mark on the fog lamp as the center mark. H line (fog light height): Draw a line across the screen so that it passes through the center mark. Line H should be at the same height as the center mark of the fog light bulb. Line V LH, V RH (center mark position of left fog lamp LH and right fog lamp RH): Draw two lines so that they intersect line H at the center marks. 5. Check the fog light convergence a/ Cover the fog lamp or remove the connector of the other side fog lamp to prevent light from the unchecked fog lamp from affecting the fog lamp convergence test. b/ Start the engine. c/ Turn on the fog lights and make sure that the dividing line is outside the standard area as shown in the drawing. 6. Adjust the fog light convergence Use a screwdriver to adjust the fog light to the standard area by turning the toe adjustment screw. Note: If the screw is adjusted too far, loosen it and then tighten it again, so that the last rotation of the light adjustment screw is clockwise. 3. Self-study questions 1. Describe the operating principle of the lighting system with automatic headlight function 2. Describe the operating principle of the lighting system with the function of rotating headlights when turning 3. Draw diagram and connect lighting system on Hyundai Porter car 4. Draw diagram and connect lighting system on Honda Accord 1992 5. Draw the lighting circuit on a 1993 Toyota Lexus LESSON 3 MAINTENANCE AND REPAIR OF SIGNAL SYSTEM I. IMPLEMENTATION GOAL After completing this lesson, students will be able to: - Distinguish between types of signals on cars - Correctly describe common symptoms and suspected areas causing damage. - Connecting signal circuits ensures technical requirements - Disassemble, install, check, maintain and repair the signal system to ensure technical requirements. - Ensure safety in work and industrial hygiene II. LESSON CONTENT 1. General description The signal system equipped on cars aims to create signals to notify other vehicles participating in traffic about the vehicle's operating status such as: stopping, parking, braking, reversing, turning... Signals are used either by light such as headlamps, brake lights, turn signals….. or by sound such as horns, reverse music…. Just like the lighting system. A signal system circuit usually consists of: battery, fuse, wire, relay, electrical load and control switch. Only some switches of the signal system are on the combination switch. The switches of other signals are usually located in different locations such as in the gearbox or brake pedal…… 2. Maintenance and repair 2.1. Turn signals and hazard lights The installation location of the turn signal is shown in Figure 3.1. The turn signal control switch is located in the combination switch under the steering wheel. Turning this switch to the right or left will make the turn signal turn right or left. The hazard light switch is used when the vehicle has a problem while participating in traffic. When the hazard light switch is turned on, all the turn signals on the vehicle will light up at a certain frequency. The hazard light switch is usually placed separately from the turn signal switch (some old cars integrate the hazard and turn signal switches on the same combination switch cluster). Figure 3.1 Turn signal switch Figure 3.2 Hazard switch The part that generates the flashing frequency for the lights is called a turn signal relay. The turn signal relay usually has 3 terminals: B (positive power supply); E (negative power supply); L (providing the turn signal switch to distribute to the lamp) 2.1.1. Circuit diagram To generate the frequency for the turn signal, a turn signal relay is used in the turn signal circuit. The current from the turn signal relay will be sent to the turn signal switch assembly to distribute the current to the turn signal lights for the driver's purpose. Figure 3.3. Schematic diagram of a turn signal circuit without a hazard switch 1. Battery; 2. Electric lock; 3. Turn signal relay; 4. Turn signal switch; 5. Turn signal lamp; 6. Turn signal lamp; 7. Hazard switch Figure 3.4 Schematic diagram of turn signal circuit with hazard switch 1. Battery; 2. Combination switch cluster; 3. Turn signal; 4. Turn signal light; 5. Turn signal relay Today's cars no longer use three-pin turn signal relays (B, L, E) but use eight-pin turn signal relays (figure 3.5) (pin number 8 is used for hazard lights). For this type, the current supplying the turn signal lights is supplied directly from the turn signal relay to the lights. div.maincontent .p { color: black; font-family:"Times New Roman", serif; font-style: normal; font-weight: normal; text-decoration: none; font-size: 14pt; margin:0pt; } div.maincontent p { color: black; font-family:"Times New Roman", serif; font-style: normal; font-weight: normal; text-decoration: none; font-size: 14pt; margin:0pt; } div.maincontent .s1 { color: black; font-family:"Times New Roman", serif; font-style: normal; font-weight: normal; text-decoration: none; font-size: 13pt; } div.maincontent .s2 { color: black; font-family:"Times New Roman", serif; font-style: italic; font-weight: normal; text-decoration: none; font-size: 14pt; } div.maincontent .s3 { color: black; font-family:"Times New Roman", serif; font-style: normal; font-weight: normal; text-decoration: none; font-size: 14pt; } div.maincontent .s4 { color: black; font-family:"Times New Roman", serif; font-style: normal; font-weight: normal; text-decoration: none; font-size: 13pt; } div.maincontent .s5 { color: black; font-family:"Times New Roman", serif; font-style: normal; font-weight: normal; text-decoration: none; font-size: 13pt; vertical-align: 1pt; } div.maincontent .s6 { color: black; font-family:"Times New Roman", serif; font-style: normal; font-weight: normal; text-decoration: none; font-size: 11pt; } div.maincontent .s7 { color: black; font-family:"Times New Roman", serif; font-style: normal; font-weight: normal; text-decoration: none; font-size: 14pt; vertical-align: -9pt; } div.maincontent .s8 { color: black; font-family:"Times New Roman", serif; font-style: normal; font-weight: normal; text-decoration: none; font-size: 11pt; } div.maincontent .s9 { color: #008000; font-family:"Times New Roman", serif; font-style: normal; font-weight: normal; text-decoration: none; font-size: 14pt; } div.maincontent .s10 { color: black; font-family:"Times New Roman", serif; font-style: italic; font-weight: normal; te
Qos Assurance Methods for Multimedia Communications zt2i3t4l5ee zt2a3gs zt2a3ge zc2o3n4t5e6n7ts low. The EF PHB requires a sufficiently large number of output ports to provide low delay, low loss, and low jitter. EF PHBs can be implemented if the output port's bandwidth is sufficiently large, combined with small buffer sizes and other network resources dedicated to EF packets, to allow the router's service rate for EF packets on an output port to exceed the arrival rate λ of packets at that port. This means that packets with PHB EF are considered with a pre-allocated amount of output bandwidth and a priority that ensures minimum loss, minimum delay and minimum jitter before being put into operation. PHB EF is suitable for channel simulation, leased line simulation, and real-time services such as voice, video without compromising on high loss, delay and jitter values. Figure 2.10 Example of EF installation Figure 2.10 shows an example of an EF PHB implementation. This is a simple priority queue scheduling technique. At the edges of the DS domain, EF packet traffic is prioritized according to the values agreed upon by the SLA. The EF queue in the figure needs to output packets at a rate higher than the packet arrival rate λ. To provide an EF PHB over an end-to-end DS domain, bandwidth at the output ports of the core routers needs to be allocated in advance to ensure the requirement μ > λ. This can be done by a pre-configured provisioning process. In the figure, EF packets are placed in the priority queue (the upper queue). With such a length, the queue can operate with μ > λ. Since EF was primarily used for real-time services such as voice and video, and since real-time services use UDP instead of TCP, RED is generally not suitable for EF queues because applications using UDP will not respond to random packet drop and RED will strip unnecessary packets. 2.2.4.2 Assured Forwarding (AF) PHB PHB AF is defined by RFC 2597. The purpose of PHB AF is to deliver packets reliably and therefore delay and jitter are considered less important than packet loss. PHB AF is suitable for non-real-time services such as applications using TCP. PHB AF first defines four classes: AF1, AF2, AF3, AF4. For each of these AF classes, packets are then classified into three subclasses with three distinct priority levels. Table 2.8 shows the four AF classes and 12 AF subclasses and the DSCP values for the 12 AF subclasses defined by RFC 2597. RFC 2597 also allows for more than three separate priority levels to be added for internal use. However, these separate priority levels will only have internal significance. PHB Class PHB Subclass Package type DSCP AF4 AF41 Short 100010 AF42 Medium 100100 AF43 High 100110 AF3 AF31 Short 011010 AF32 Medium 011100 AF33 High 011110 AF2 AF21 Short 010010 AF22 Medium 010100 AF23 High 010110 AF1 AF11 Short 001010 AF12 Medium 001100 AF13 High 001110 Table 2.8 AF DSCPs The AF PHB ensures that packets are forwarded with a high probability of delivery to the destination within the bounds of the rate agreed upon in an SLA. If AF traffic at an ingress port exceeds the pre-priority rate, which is considered non-compliant or “out of profile”, the excess packets will not be delivered to the destination with the same probability as the packets belonging to the defined traffic or “in profile” packets. When there is network congestion, the out of profile packets are dropped before the in profile packets are dropped. When service levels are defined using AF classes, different quantity and quality between AF classes can be realized by allocating different amounts of bandwidth and buffer space to the four AF classes. Unlike EF, most AF traffic is non-real-time traffic using TCP, and the RED queue management strategy is an AQM (Adaptive Queue Management) strategy suitable for use in AF PHBs. The four AF PHB layers can be implemented as four separate queues. The output port bandwidth is divided into four AF queues. For each AF queue, packets are marked with three “colors” corresponding to three separate priority levels. In addition to the 32 DSCP 1 groups defined in Table 2.8, 21 DSCPs have been standardized as follows: one for PHB EF, 12 for PHB AF, and 8 for CSCP. There are 11 DSCP 1 groups still available for other standards. 2.2.5.Example of Differentiated Services We will look at an example of the Differentiated Service model and mechanism of operation. The architecture of Differentiated Service consists of two basic sets of functions: Edge functions: include packet classification and traffic conditioning. At the inbound edge of the network, incoming packets are marked. In particular, the DS field in the packet header is set to a certain value. For example, in Figure 2.12, packets sent from H1 to H3 are marked at R1, while packets from H2 to H4 are marked at R2. The labels on the received packets identify the service class to which they belong. Different traffic classes receive different services in the core network. The RFC definition uses the term behavior aggregate rather than the term traffic class. After being marked, a packet can be forwarded immediately into the network, delayed for a period of time before being forwarded, or dropped. We will see that there are many factors that affect how a packet is marked, and whether it is forwarded immediately, delayed, or dropped. Figure 2.12 DiffServ Example Core functionality: When a DS-marked packet arrives at a Diffservcapable router, the packet is forwarded to the next router based on Per-hop behavior is associated with packet classes. Per-hop behavior affects router buffers and the bandwidth shared between competing classes. An important principle of the Differentiated Service architecture is that a router's per-hop behavior is based only on the packet's marking or the class to which it belongs. Therefore, if packets sent from H1 to H3 as shown in the figure receive the same marking as packets from H2 to H4, then the network routers treat the packets exactly the same, regardless of whether the packet originated from H1 or H2. For example, R3 does not distinguish between packets from h1 and H2 when forwarding packets to R4. Therefore, the Differentiated Service architecture avoids the need to maintain router state about separate source-destination pairs, which is important for network scalability. Chapter Conclusion Chapter 2 has presented and clarified two main models of deploying and installing quality of service in IP networks. While the traditional best-effort model has many disadvantages, later models such as IntServ and DiffServ have partly solved the problems that best-effort could not solve. IntServ follows the direction of ensuring quality of service for each separate flow, it is built similar to the circuit switching model with the use of the RSVP resource reservation protocol. IntSer is suitable for services that require fixed bandwidth that is not shared such as VoIP services, multicast TV services. However, IntSer has disadvantages such as using a lot of network resources, low scalability and lack of flexibility. DiffServ was born with the idea of solving the disadvantages of the IntServ model. DiffServ follows the direction of ensuring quality based on the principle of hop-by-hop behavior based on the priority of marked packets. The policy for different types of traffic is decided by the administrator and can be changed according to reality, so it is very flexible. DiffServ makes better use of network resources, avoiding idle bandwidth and processing capacity on routers. In addition, the DifServ model can be deployed on many independent domains, so the ability to expand the network becomes easy. Chapter 3: METHODS TO ENSURE QoS FOR MULTIMEDIA COMMUNICATIONS In packet-switched networks, different packet flows often have to share the transmission medium all the way to the destination station. To ensure the fair and efficient allocation of bandwidth to flows, appropriate serving mechanisms are required at network nodes, especially at gateways or routers, where many different data flows often pass through. The scheduler is responsible for serving packets of the selected flow and deciding which packet will be served next. Here, a flow is understood as a set of packets belonging to the same priority class, or originating from the same source, or having the same source and destination addresses, etc. In normal state when there is no congestion, packets will be sent as soon as they are delivered. In case of congestion, if QoS assurance methods are not applied, prolonged congestion can cause packet drops, affecting service quality. In some cases, congestion is prolonged and widespread in the network, which can easily lead to the network being "frozen", or many packets being dropped, seriously affecting service quality. Therefore, in this chapter, in sections 3.2 and 3.3, we introduce some typical network traffic load monitoring techniques to predict and prevent congestion before it occurs through the measure of dropping (removing) packets early when there are signs of impending congestion. 3.1. DropTail method DropTail is a simple, traditional queue management method based on FIFO mechanism. All incoming packets are placed in the queue, when the queue is full, the later packets are dropped. Due to its simplicity and ease of implementation, DropTail has been used for many years on Internet router systems. However, this algorithm has the following disadvantages: − Cannot avoid the phenomenon of “Lock out”: Occurs when 1 or several traffic streams monopolize the queue, making packets of other connections unable to pass through the router. This phenomenon greatly affects reliable transmission protocols such as TCP. According to the anti-congestion algorithm, when locked out, the TCP connection stream will reduce the window size and reduce the packet transmission speed exponentially. − Can cause Global Synchronization: This is the result of a severe “Lock out” phenomenon. Some neighboring routers have their queues monopolized by a number of connections, causing a series of other TCP connections to be unable to pass through and simultaneously reducing the transmission speed. After those monopolized connections are temporarily suspended, Once the queue is cleared, it takes a considerable amount of time for TCP connections to return to their original speed. − Full Queue phenomenon: Data transmitted on the Internet often has an explosion, packets arriving at the router are often in clusters rather than in turn. Therefore, the operating mechanism of DropTail makes the queue easily full for a long period of time, leading to the average delay time of large packets. To avoid this phenomenon, with DropTail, the only way is to increase the router's buffer, this method is very expensive and ineffective. − No QoS guarantee: With the DropTail mechanism, there is no way to prioritize important packets to be transmitted through the router earlier when all are in the queue. Meanwhile, with multimedia communication, ensuring connection and stable speed is extremely important and the DropTail algorithm cannot satisfy. The problem of choosing the buffer size of the routers in the network is to “absorb” short bursts of traffic without causing too much queuing delay. This is necessary in bursty data transmission. The queue size determines the size of the packet bursts (traffic spikes) that we want to be able to transmit without being dropped at the routers. In IP-based application networks, packet dropping is an important mechanism for indirectly reporting congestion to end stations. A solution that prevents router queues from filling up while reducing the packet drop rate is called dynamic queue management. 3.2. Random elimination method – RED 3.2.1 Overview RED (Random Early Detection of congestion; Random Early Drop) is one of the first AQM algorithms proposed in 1993 by Sally Floyd and Van Jacobson, two scientists at the Lawrence Berkeley Laboratory of the University of California, USA. Due to its outstanding advantages compared to previous queue management algorithms, RED has been widely installed and deployed on the Internet. The most fundamental point of their work is that the most effective place to detect congestion and react to it is at the gateway or router. Source entities (senders) can also do this by estimating end-to-end delay, throughput variability, or the rate of packet retransmissions due to drop. However, the sender and receiver view of a particular connection cannot tell which gateways on the network are congested, and cannot distinguish between propagation delay and queuing delay. Only the gateway has a true view of the state of the queue, the link share of the connections passing through it at any given time, and the quality of service requirements of the traffic flows. The RED gateway monitors the average queue length, which detects early signs of impending congestion (average queue length exceeding a predetermined threshold) and reacts appropriately in one of two ways: − Drop incoming packets with a certain probability, to indirectly inform the source of congestion, the source needs to reduce the transmission rate to keep the queue from filling up, maintaining the ability to absorb incoming traffic spikes. − Mark “congestion” with a certain probability in the ECN field in the header of TCP packets to notify the source (the receiving entity will copy this bit into the acknowledgement packet). Figure 3. 1 RED algorithm The main goal of RED is to avoid congestion by keeping the average queue size within a sufficiently small and stable region, which also means keeping the queuing delay sufficiently small and stable. Achieving this goal also helps: avoid global synchronization, not resist bursty traffic flows (i.e. flows with low average throughput but high volatility), and maintain an upper bound on the average queue size even in the absence of cooperation from transport layer protocols. To achieve the above goals, RED gateways must do the following: − The first is to detect congestion early and react appropriately to keep the average queue size small enough to keep the network operating in the low latency, high throughput region, while still allowing the queue size to fluctuate within a certain range to absorb short-term fluctuations. As discussed above, the gateway is the most appropriate place to detect congestion and is also the most appropriate place to decide which specific connection to report congestion to. − The second thing is to notify the source of congestion. This is done by marking and notifying the source to reduce traffic. Normally the RED gateway will randomly drop packets. However, if congestion If congestion is detected before the queue is full, it should be combined with packet marking to signal congestion. The RED gateway has two options: drop or mark; where marking is done by marking the ECN field of the packet with a certain probability, to signal the source to reduce the traffic entering the network. − An important goal that RED gateways need to achieve is to avoid global synchronization and not to resist traffic flows that have a sudden characteristic. Global synchronization occurs when all connections simultaneously reduce their transmission window size, leading to a severe drop in throughput at the same time. On the other hand, Drop Tail or Random Drop strategies are very sensitive to sudden flows; that is, the gateway queue will often overflow when packets from these flows arrive. To avoid these two phenomena, gateways can use special algorithms to detect congestion and decide which connections will be notified of congestion at the gateway. The RED gateway randomly selects incoming packets to mark; with this method, the probability of marking a packet from a particular connection is proportional to the connection's shared bandwidth at the gateway. − Another goal is to control the average queue size even without cooperation from the source entities. This can be done by dropping packets when the average size exceeds an upper threshold (instead of marking it). This approach is necessary in cases where most connections have transmission times that are less than the round-trip time, or where the source entities are not able to reduce traffic in response to marking or dropping packets (such as UDP flows). 3.2.2 Algorithm This section describes the algorithm for RED gateways. RED gateways calculate the average queue size using a low-pass filter. This average queue size is compared with two thresholds: minth and maxth. When the average queue size is less than the lower threshold, no incoming packets are marked or dropped; when the average queue size is greater than the upper threshold, all incoming packets are dropped. When the average queue size is between minth and maxth, each incoming packet is marked or dropped with a probability pa, where pa is a function of the average queue size avg; the probability of marking or dropping a packet for a particular connection is proportional to the bandwidth share of that connection at the gateway. The general algorithm for a RED gateway is described as follows: [5] For each packet arrival Caculate the average queue size avg If minth ≤ avg < maxth div.maincontent .s1 { color: black; font-family:"Times New Roman", serif; font-style: normal; font-weight: normal; text-decoration: none; font-size: 15pt; } div.maincontent .s2 { color: black; font-family:"Times New Roman", serif; font-style: normal; font-weight: bold; text-decoration: none; font-size: 15pt; } div.maincontent .p { color: black; font-family:"Times New Roman", serif; font-style: normal; font-weight: normal; text-decoration: none; font-size: 14pt; margin:0pt; } div.maincontent p { color: black; font-family:"Times New Roman", serif; font-style: normal; font-weight: normal; text-decoration: none; font-size: 14pt; margin:0pt; } div.maincontent .s3 { color: black; font-family:"Times New Roman", serif; font-style: normal; font-weight: bold; text-decoration: none; font-size: 14pt; } div.maincontent .s4 { color: black; font-family:"Times New Roman", serif; font-style: normal; font-weight: normal; text-decoration: none; font-size: 14pt; } div.maincontent .s5 { color: black; font-family:"Times New Roman", serif; font-style: italic; font-weight: normal; text-decoration: none; font-size: 14pt; } div.maincontent .s6 { color: black; font-family:"Times New Roman", serif; font-style: italic; font-weight: bold; text-decoration: none; font-size: 14pt; } div.maincontent .s7 { color: black; font-family:Wingdings; font-style: normal; font-weight: normal; text-decoration: none; font-size: 14pt; } div.maincontent .s8 { color: black; font-family:Arial, sans-serif; font-style: italic; font-weight: bold; text-decoration: none; font-size: 15pt; } div.maincontent .s9 { color: black; font-family:"Times New Roman", serif; font-style: normal; font-weight: bold; text-decoration: none; font-size: 14pt; } div.maincontent .s10 { color: black; font-family:"Times New Roman", serif; font-style: normal; font-weight: normal; text-decoration: none; font-size: 9pt; vertical-align: 6pt; } div.maincontent .s11 { color: black; font-family:"Times New Roman", serif; font-style: normal; font-weight: normal; text-decoration: none; font-size: 13pt; } div.maincontent .s12 { color: black; font-family:"Times New Roman", serif; font-style: normal; font-weight: normal; text-decoration: none; font-size: 10pt; } div.maincontent .s13 { color: black; font-family:"Times New Roman", serif; font-style: normal; font-weight: normal; text-d
d-blast algorithm in mimo technology - 8
Rate of Vitamin D Deficiency and Frequency of Acute Respiratory Infections in Children Under 5 Years Old in An Lao District, Hai Phong City
Effects of Voltage (A); Kcl Concentration (B); Electrolysis Time (C); and Stirring Time (D) on Hg Signal (Ii)

yes

Pole

This belt has a fairly small magnitude , so it is suitable for

call

is pole

band

extra .

Clear between the poles

this big guy and the two poles

right side main

There are two extremes .

It has been proven that if there are N narrow gaps between two circles , then

pole

The main circuit will have N -1 poles .

small and N-2 pole

husband

Figure 3.24 represents

diffraction pattern through three narrow slits and the position of the maxima and minima. If N is large, the width of the main maxima is narrow, and the main maxima observed will be sharp. Because the secondary maxima are much less bright than the main maxima, we do not need to pay attention to them and the diffraction pattern through many narrow slits will be a series of parallel, evenly spaced bright lines. From the formula () we see: to observe the main maxima, then  d ( because sin  1) .

3.4.3. Diffraction grating

a. Concept

A diffraction grating is a system of many identical narrow slits of width b , lying parallel and equidistant on the same plane. The distance d between two consecutive slits is called the period of the grating.

b. Classification

There are two types of diffraction gratings: reflection gratings and transmission gratings.

3.4.4. Diffraction on crystals

The constituent atoms (molecules or ions )

Figure 3.25. Diffraction grating

Figure 3.26.

so crystalline solid can be

about to

arranged in a periodic structure called

is a crystal lattice in which the positions of the

atoms (molecules or ions ) are called lattice nodes. The distance between lattice nodes,

characteristic for periodicity , which is

call

is the period of the crystal lattice. Projected onto

a single beam of X-rays , each node of the network becomes how many

far and

The crystal lattice acts as a self-healing mechanism with the period being the period of the crystal lattice .

The X-ray beam will radiate in many directions, but only in

direction of reflection (direction where the angle of reflection is equal to the angle of incidence), the intensity of

how many

far enough away to see clearly

how much

far

Consider the diffracted rays in the direction of mirror reflection. The optical path difference between the two reflected rays on the two planes 11' and 22' is:

 2d sin (3.24)

The optical path difference between two reflected rays on two planes 11' and 33' is 2 . Thus, according to the mirror reflection method, there will be

Figure 3.27. Diffraction on crystals

a diffracted beam with optical path differences of  , 2 , 3 , ... , the rays

far away

will interfere with each other and give a diffraction maximum if two successive diffracted rays have a path difference equal to an integer number of wavelengths :

 2d sin  k 

or:

sin  k , (3.25)

with d being the distance between two atomic planes of the crystalline solid (the period of the crystal lattice). The formula ( 3.25) is called the Vulf-Bragg formula. This is the basic formula for analyzing the structure of crystalline solids by X- rays . If

know the wavelengthof X-rays and angle measurement we can determine

d means to determine the structure of the crystal lattice.

period

1. Present gratitude

how much

CHAPTER 3 SUMMARY

away from light

The phenomenon of light rays being deviated from rectilinear propagation when passing near objects

small enough obstacle

2. Huygens - Fresnel principle:

a. Statement

call

is a present

how much

light radiation

Lip

point in space

light waves from real sources

send to

All become secondary light sources that emit light waves forward .

The amplitude and phase of the secondary source are the amplitude and phase given by the actual source.

cause

out of ear

location of the source

b. Expression of the resulting wave at M

x  dx ( M )   A (  ,  0) cos  ( t  r 1 r 2) dS

( S )

3. Fresnel sphere method

r 1 r 2v

The total amplitude due to the Fresnel zones at M is:

a a 1 a 2 a 3 a 4 a 5 a 6 ...

4. How far is the spherical wave through the round hole?

Pressure

By using the Fresnel bridge method , we can calculate

amplitude of light

general morning

ears

M, distance R from source S :

a a 1 a n ,

2 2

The sign "+" corresponds to odd n, the sign "-" corresponds to even n.

Consider the cases:

When there is no screen P or the size of the circular hole is very large n : n  , a n  0

should be the brightness of ear M:

2 a 2

I 0 ka

k1.

If the hole contains the required odd number :

I  ka 2  k ( a 1  a n ) 2  I ,

2 2 0

Point M is brighter without screen P.

In particular, if the hole is a single demand: n = 1 a a 1

I ka2  4 I .

The light intensity is 4 times higher than without the hole, so point M is very bright.

If the hole contains an even number , request:

I  ka 2  k ( a 1  a n ) 2  I ,

2 2 0

Point M is darker when there is no circular hole.

In particular, if the circular hole contains two spheres then : a a 1 a 2

 0 I  0 ,

2 2

Point M is completely dark.

After

Point M may be brighter or darker than without the hole .

depending on the size of the hole and the position of the viewing screen.

5. How far is the spherical wave passing through the circular disk?

The amplitude of light oscillation at M is:

a a m  1 a m  2 a m  3 a m  4 a m  5  ...

 a  a m  1

 I  ka 2  k ( a m  1 ) 2  k ( a 1 ) 2  I .

2 2 0

So:If the disk only covers a small part of the zone, then at M we always have a bright spot with a light intensity slightly less than the light intensity at M in the absence of an occluding object.

6. How much?

propagation of a plane wave through a narrow slit

Pressure

By using Fresnel bridge method we can calculate

knife amplitude

total luminosity

ears

a point M on the observation screen.

As a result , we have the following extreme conditions:

big, big

small

narrow slit radiation

Pole

band

between :

sin  0

Pole

how much

distant:

sin   ;  2 ;

 3 

; ...

Pole

band

how much

distant:

sin   3 ;  5 ;  7 ; ...

2b 2b 2b

On the intensity distribution graph we see the pole

band

very bright , the

pole

band

how much

radiation of order k = 1,2,3... lying between the poles

how much

radiation and

bilateral symmetrical distribution

band

keep a . pole

band

between the two widths

pair of poles

band

different. According to theoretical calculations, the luminous intensity of the

pole

band

how much

radiation follows the following formula :

I 0 : I 1 : I 2 : I 3 : ...  1: 0, 045 : 0, 016 : 0, 008 : ...

7. Diffraction on crystals

For crystalline solids, the crystal lattice plays an indispensable role .

three-dimensional space. The many

X - ray radiation on the man buttons

g gives us the result :

2d sin k , d is the distance between two mandrels

g , is called the lattice constant. This

is the Vulf-Bragg formula, which is used to determine the structure of crystalline solids.

THEORETICAL QUESTIONS

1. Define

present gratitude

how much

away from light. Using Huygens' principle

qualitative explanation of the present

how much

distant.

2. State the Huygens-Fresnel principle.

3. Present the Fresnel sphere method: how to divide the zone, calculate the light intensity and the total amplitude.

4. Current survey

how much

light through a small round hole and through a disc

circle, state the difference between the two phenomena above.

5. Describe the current situation

how much

light through a narrow slit

. Find conditions

pole

big, big

how much

diffraction pattern of a plane wave passing through a

narrow gap

6. Investigate the diffraction through N slits of a plane wave, define the main and secondary minima, main and secondary maxima. Draw the diffraction pattern of a plane wave through three narrow slits, indicating the positions of the maxima and minima.

7. Present much

X- ray scattering on crystals. Vulf - Bragg formula. State

application

g of the present

how much

X - ray

CHAPTER 3 EXERCISES

Lesson 3.1.

A light source S emits monochromatic light with a wavelength of 550nm , shining on a screen E 11m away from S. At the point between screen E and source S there is a screen containing a circular hole with a diameter of 4.2mm . Indicate whether the brightness at the center of the diffraction pattern obtained on the screen is greater or less than the brightness at that spot without the screen.

Lesson 3.2.

Monochromatic light has a wavelength of 500nm , shining perpendicularly into a slit with a width of 0.02mm . Find the width of the slit image on a screen placed 1m from the slit (the lens is placed close to the slit).

Lesson 3.3.

A parallel beam of light with a wavelength of 500nm is irradiated perpendicularly to a diffraction grating. A converging lens is placed near the grating. The distance from the screen to the lens is 1m . The distance between the two maximum lines of the first-order spectrum is 20.2cm . Determine:

a. Period d of the grating.

b. Number of lines per mm of grating.

Lesson 3.4.

Shine a chromatic light with wavelength  = 0.5  m into a circular hole with radius

unknown. The point light source is placed 2m away from the circular hole , and an observation screen is placed 2m behind the circular hole . What is the radius of the circular hole so that the center of the diffraction pattern is the darkest?

Lesson 3.5.

A point light source shines a monochromatic light with wavelength  = 0.5  m into a circular hole with radius r = 1mm . The distance from the light source to the circular hole is R = 1m. Find the distance from the circular hole to the observation screen so that the circular hole contains three Fresnel lenses .

Lesson 3.6.

A good screen

placed at a wavelength distance from the light source

 =0.5  m at a distance of 2m . A round hole is placed between the screen and the light source.

diameter 0.2cm . Find the number of Fresnel spheres that the circular hole cannot fit .

Lesson 3.7.

Place an observation screen ̛ n away from a point light source emitting measured light.

wavelength  = 0.6  m in a distance x . In the middle of the distance x , place a disc

round

small opaque object with diameter 1mm . What is x so that point M is 0 on the screen?

The observation has a brightness similar to that of a circular object, knowing that point M is 0.and source

light is evenly distributed on the axis

Lesson 3.8.

door

round.

A parallel beam of light with wavelength λ = 0.589  m is projected straight

angle with a narrow slit of width b=2  m . Ask which diffraction minima are

observe from any angle

Lesson 3.9.

how far? ( compared to the original position )

Shine a parallel, sharp beam of light perpendicular to a narrow slit .

The wavelength of light is 16 times the width of the slit .

. Ask for the first diffraction minimum

At what angle is the three objects observed ?

Lesson 3.10.

A beam of light is

perpendicular to a line from a certain angle . Knowing that the angle

how much

The distance for the spectral distance λ 1 =0.65  m in the second-order spectrum is

φ 1 =45 0 . Determine the angle of the third order spectrum.

Lesson 3.11.

far infrared with spectral density λ 2 = 0.5  m

Given a plane circuit with period d = 2μm . After the circuit , place a

converging lens,

on the observation screen placed at the focal plane of the human lens

We observe that the distance between the two first- order spectra corresponds to the wavelength

λ 1 = 0.4044μm and λ 2 = 0.4047μm equals 0.1mm . Determine the focal length of the lens.

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