Teaching Objectives and Learning Outcome Test:


2.3.2. Teaching objectives and learning outcome test:

2.3.2.1. Teaching objectives:

a) Objectives while studying:


Know how to use the formula for calculating the work of gravity to construct the formula for gravitational potential energy and the expression relating the change in gravitational potential energy and the work of gravity.

Know how to calculate the work of elastic force, reasoning is similar to

in the case of elastic potential energy.

gravitational force to

Concept and expression building

Apply the formula for calculating gravitational potential energy and elastic potential energy to solve simple problems.

b) Objectives after studying:

The statement defines gravity and uniform gravity.

State the definition and write the expression of gravitational potential and gravitational potential energy.

power

Write the formula relating gravitational potential energy.

between the work of gravity and the

variable

Apply the formula to determine potential energy in which we can distinguish:

+ The work of gravity always reduces potential energy. When potential energy increases, it means that gravity does negative work, and vice versa.

+ Potential energy at each location can be different depending on how the potential energy reference is chosen. From there, you can choose the appropriate potential energy reference in solving problems related to potential energy.

2.3.2.2. Test of learning outcomes:

Question 1 : Define and write the expressions of gravitational potential energy and elastic potential energy.

Question 2 : When an object from height z, with the same initial velocity, flies to the ground in different paths:

A. The magnitude of the velocity hitting the ground is equal.

B. equal fall time.

C. The work of gravity is equal.

D. The acceleration of fall is equal. Choose the wrong sentence.


Question 3. An objectwith mass m=3kg is placed at

one

mind in mind


1

field and has potential energy at that position equal to Wt = 500 J. Let the object fall freely


2

to the ground, where the potential energy of the object is Wt = 900 J.

a) Ask from what height above the ground did the object fall?

b) Determine where the potential origin was chosen?

c) Find the velocity of the object when it passes through the origin of potential energy.

Answer:

Question 1: The gravitational potential energy of an object at a height z above the ground is the form of interaction energy between the Earth and the object, calculated by the work of gravity acting on the object when the object falls from height z to the ground.

Expression: Wt= mgz.

The elastic potential energy of a spring when it is deformed is the energy of the spring when it is deformed, calculated by the work of the elastic force acting on it.

springs up when taking it from the form.

state of deformation

static state

Expression:

Question 2: Answer A.

W  1 k ( l )2

t 2

Question 3: Choose the positive direction of the z axis pointing up.

1 2

a) Wt  Wt  mg ( z 1  z 2 )  500  (900)  1400 J .

m.

z  1400  47.6

3.9.8

b) At the origin of potential energy, z = 0

W  mgz  500J � z

 500  17.0

t1 1 1

3.9.8 m

The initial position is 17m higher than the original position of the potential energy. The potential energy at the ground can be checked:


2

Wt  mgz

2  900J � z2

  900  30.6 m.

3.9.8

That is, the ground is 30.6 m lower than the position of the origin of potential energy.


2gz 1

2.9,8.17

c) v    18.25 m/s.


2.3.3. Teaching aids:

1. Teacher:

Real life examples to illustrate how objects with gravitational potential energy and elastic potential energy can do work.

2. Students:

Review the concepts of gravity, gravitational potential energy, and elastic potential energy learned in the 8th grade curriculum.

Review the concept of work and how to calculate the work of force.

2.3.4. Teaching and learning process:

2.3.4.1. Check, prepare starting conditions and pose the problem in the lesson:

Review old lessons, prepare departure conditions:

State the definition of work and the expression for calculating work in the general case?

State the concept of kinetic energy, the relationship between work and kinetic energy change?

between the work of the force

Problem proposal: In the following cases:

+ A heavy object is up high

+ The bow is drawn.

+ Hammer the machine at a certain height.

Do these objects have energy? Why? If so, what form of energy is it?

HS: Objects have energy because they have the ability to do work. That form of energy is potential energy.


How many types of potential energy are there?

HS: There are two types of potential energy: gravitational potential energy and elastic potential energy.

We know that the energy associated with mechanical motion is called mechanical energy. In the previous lesson, we learned about a form of mechanical energy, kinetic energy. In today's lesson, we will study the second form of energy, potential energy (the teacher writes the topic on the board).

2.3.4.2. Solving learning problems:

Problem 1: Concept of gravity.


Teacher activities

Student activities

All objects around the Earth are affected by the gravitational force caused by the Earth, this force is known as gravity.

There is a gravitational field around the Earth. So what are the signs to recognize the gravitational field?

Write the expression of gravity?

If an object is placed in different positions in space, is the force of gravity acting on the object the same? Why?

Notice: In a space that is not too large, g at every point has parallel directions, the same direction and the same magnitude. Gravity

This is called uniform gravity.


HS: All objects in a gravitational field are affected by gravity.

HS: r  m r.

P g

HS: Not the same because gravitational acceleration depends on geographical location.

Maybe you are interested!

Teaching Objectives and Learning Outcome Test:

Student activities

Problem 2: Concept of gravitational potential energy.


Teacher activities


Problem proposal: In grade 8, you learned that an object at any height

compared to the ground has the ability to do work

so objects store energy in the form of potential energy.

Consider the following example:

Release

a hammer from the degree

high z fall

down to hit the pile making the pile go deep into the ground a distance s.

What force acts on the hammer and does work when the hammer falls?

When the height z of the hammer increases, when the hammer


HS: Gravity acts and does work when the hammer falls.

HS: The higher the hammer height, the more the pile sinks.

fall, how much?

Pile settlement changes as

position

Overview: When the hammer is at height z relative to

ground, energy storage hammer. Form

This energy is called potential field.

weight

The gravitational potential energy of an object is the form of interaction energy between the Earth and the object; it depends on the position of the object in the gravitational field.

When falling from a height z greater, the weight

force acting on the hammer to generate power

large, hammer power

The larger (the more the pile sinks), the greater the potential energy of the hammer.


HS: Yes.


gravitational force of

So the potential energy of an object at a height

material

proportional to the degree

height of


something relative to the ground is defined object to ground.

like

position

which? (have connection)

what with

height of the object?).

An object at height z has potential energy because the object has the ability to do work. On the other hand, gravity acts on the object to do work.

during the falling process, so it can be calculated

gravitational potential energy of an object

through the work of gravity acting on the object.

Calculate the work done by gravity when the hammer falls from height z to the ground?


Notice: The energy value that an object has due to the object being at a height z above the ground

HS: Work done by gravity:

A = Pz = mgz.

HS: Write an expression defining gravitational potential energy.

Wt = mgz.

earth is called gravitational potential energy, sign

The signal is Wt, which is calculated by weight.

force that makes an object fall from a height to the ground

high


HS: Unit


of the world


weight

Wt = A = mgz.

Define the unit of potential energy?

Field is the unit of energy. [Wt] = J.


Introduce the concept of potential energy:

Potential energy is a relative energy quantity, depending on position in space. Therefore, the potential energy reference must be chosen.

Landmark

ability is taste

the place where

HS: Potential energy reference point chosen at the surface


the energy of the object is zero.

According to the above formula, where is the potential energy reference chosen?

However, one can also choose the potential energy reference at another position for convenience in calculation. Specifically, we consider the following problem:

Request to answer question C3:

If the potential energy mark is chosen at position O, then at which point:

potential energy = 0 ?

potential energy > 0 ?

potential energy < 0 ?

land.

HS: If we choose the potential energy point at

O then:

At O: Wt= 0. At A: WtA>0.

At B: WtB< 0.


Problem 3: Find the relationship between potential energy change and work of gravity.

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